This circle has the centre at the origin and a radius of 1 unit. The point P can move around the circumference of the circle. At point P the \(x\)-coordinate is \(\cos{\theta}\) and the \(y ...

times {m_{tgt}} = - 1\) to find the gradient of the tangent. Find the equation of the tangent to the circle \({x^2} + {y^2} - 2x - 2y - 23 = 0\) at the point \(P(5, - 2)\) which lies on the circle.

Once the tangent is found you can use it to find the gradient of the graph by using the following formula: \(\text{Gradient to the curve =}~\frac {y_2-y_1} {x_2-x_1}\) where \(({x_1,~y_1})\) ...

This circle has the centre at the origin and a radius of 1 unit. The point P can move around the circumference of the circle. At point P the \(x\)-coordinate is \(\cos{\theta}\) and the \(y ...