First, we need to find which number when substituted into the equation will give the answer zero. \(f(1) = {(1)^3} + 4{(1)^2} + (1) - 6 = 0\) Therefore \((x - 1)\)is ...

We can solve polynomials by factoring them in terms of degree and ... This type of equation is also referred to as a cubic equation because it involves a polynomial of degree three.